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82=1.5t^2
We move all terms to the left:
82-(1.5t^2)=0
We get rid of parentheses
-1.5t^2+82=0
a = -1.5; b = 0; c = +82;
Δ = b2-4ac
Δ = 02-4·(-1.5)·82
Δ = 492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{492}=\sqrt{4*123}=\sqrt{4}*\sqrt{123}=2\sqrt{123}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{123}}{2*-1.5}=\frac{0-2\sqrt{123}}{-3} =-\frac{2\sqrt{123}}{-3} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{123}}{2*-1.5}=\frac{0+2\sqrt{123}}{-3} =\frac{2\sqrt{123}}{-3} $
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